2019 WAEC EXPO PHYSICS THEORY & OBJ QUESTIONS AND ANSWERS

PHYSICS OBJ:
1-10: CBBBCACBCB
11-20: CCCABBBDCD
21-30: CBDADCDDDA
31-40: BDDBBCAABC
41-50: ABDABDBCBA

(5a)
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(5b)
Holes are spaces left by electrons in an atom in a crystal lattice. They are positively charged. (11ai)
Force is anything that causes motion.Its S.I unit is Newton(N) or Kgm/s^2

(11aii)
(i) Static friction
(ii) Dynamic friction

(11bi)
DRAW THE GRAPH

(11bii)
Deceleration
during last 5s=18/5=3.6m/s^2

(11biii)
Total distance=S1+S2+S3+S4
=(3020)+1/2(18+30)(6)+(1810)=(1/2518)
=600+144+180+45
=969metres

(1)
Mass = 20g = (20/100)kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25

V = 5m/s

(3)
(i) magnetic declination
(ii) magnetic inclination

(iii) horizontal components

(3)
(i) Photoelectricity
(ii) Thermonic equation

(iii) Compton effect

(4)
(i) magnetic declination
(ii) magnetic inclination
(iii) horizontal components

================================

(6a)
Principle of operation of fiber optics state that the density of
transparent glass and the refractive index is greater than the
density of the two mirrors. It makes use of the principle of the
total internal reflection.
(6b)
(i) It is used to view deep down the throat of a patient
(ii) It is used to conveying information

================================

(9ai)
Latent heat is energy released or absorbed, by a body or a
thermodynamic system, during a constant-temperature process.
(9aii)
(i)surface area in contact with atmosphere
(ii)nature of the liquid
(9bi)
The rate of absorption of heat by clay pot is less than the rate of
absorption of heat by plastics. Also, water gets evaporated in a
clay pot which the evaporation causes cooling; so water in a clay
pot remains cool
(9bii)
An increase in pressure in the cooker increase the ambient
temperature in the cooker hence the food cooks faster
(9c)
(i) Change in the state of a substance
(ii) Increase in temperature
(9di)
Heat supplied = m1
lvt = m1
12401400=1.51
L=12
401400/1.5
L=672000/1.5= 448,000J/kg
Laten heat of fusion of the body = 4.48
10^5J/Kg
(9dii)
lvt=mc D tita
124072=1.5c60
C=124072/1.5*60
C=384J/Kg/K
Specific heat capacity of the body =384J/Kg/K

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